1.

If α=1+12+13+⋯⋯+1101 and β=99∑r=1r(102−r)(101−r), then the value of α+β is

Answer»

If α=1+12+13+⋯⋯+1101 and β=99∑r=1r(102−r)(101−r), then the value of α+β is



Discussion

No Comment Found