1.

If A−1=⎡⎢⎣−1350−2−2002⎤⎥⎦ then the value of 14(det(adj(adj A)))–1 is equal to

Answer» If A−1=⎡⎢⎣−1350−2−2002⎤⎥⎦ then the value of 14(det(adj(adj A)))–1 is equal to




Discussion

No Comment Found