1.

If A = {:[(1, 2), (3,4)]:} , then 2A^(-1) =

Answer»

3I - A
5 I - A
A - 5I
3A + I

Solution :`A^(2) - 5A - 2I = 0rArrA - 5 I - 2A^(-1) = 0`
2A^(-1) = A - 5I`


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