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If `A=[(1+2i,i),(-I,1-2i)]`, where `i=sqrt(-1)`, then `A(adjA)=`. . .A. `-2l`B. 2lC. 5 lD. 4l |
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Answer» Correct Answer - D We have, `A = [{:(1 +2i, i),(-I,1-2i):}]` `:. |A| = |{:(1 + 2i, i),(-I,1-2i):}| = (1 + 2i) (1 - 2i) + i^(2)` `= 1 - (2i)^(2) + (-1) = 1 + 4 - 1 = 4` `:. A` (adj A) = |A| I = 4I |
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