If A=⎡⎢⎢⎢⎢⎣1√52√5−2√51√5⎤⎥⎥⎥⎥⎦, B=[10i1], i=√−1 and Q=ATBA, then the inverse of the matrix AQ2021 AT is equal to

If A=⎡⎢⎢⎢⎢⎣1√52√5−2√51√5⎤⎥⎥⎥⎥⎦, B=[1

1.	If A=⎡⎢⎢⎢⎢⎣1√52√5−2√51√5⎤⎥⎥⎥⎥⎦, B=[10i1], i=√−1 and Q=ATBA, then the inverse of the matrix AQ2021 AT is equal to
Answer» If $A = ⎡ ⎢⎢⎢⎢ ⎣ \begin{matrix} \frac{1}{\sqrt{5}} & \frac{2}{\sqrt{5}} \frac{- 2}{\sqrt{5}} & \frac{1}{\sqrt{5}} \end{matrix} ⎤ ⎥⎥⎥⎥ ⎦, B = [\begin{matrix} 1 & 0 i & 1 \end{matrix}], i = \sqrt{- 1}$ and $Q = A^{T} B A,$ then the inverse of the matrix $A Q^{2021} A^{T}$ is equal to

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If A=⎡⎢⎢⎢⎢⎣1√52√5−2√51√5⎤⎥⎥⎥⎥⎦, B=[10i1], i=√−1 and Q=ATBA, then the inverse of the matrix AQ2021 AT is equal to

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