1.

If a_(1), a_(2),…a_(n) are in H.P. then a_(1).a_(2) + a_(2).a_(3) + a_(3).a_(4) + …+ a_(n-1) .a_(n)=

Answer»

`na_(1)a_(N)`
`(n -1) a_(1)a_(n)`
`n(a_(1) - a_(n))`
`(n - 1) (a_(1) - a_(n))`

ANSWER :B


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