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If (a_(1) + ib_(1)) (a_(2) + ib_(2)) … (a_(n) + ib_(n)) = A + iB then Tan^(-1) ((b_(1))/(a_(1))) + Tan^(-1) ((b_(2))/(a_(2))) + …. + Tan^(-1) ((b_(n))/(a_(n))) = |
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Answer» `Tan^(-1) ((A)/(B))` |
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