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If a `10muF` capacitor is to have an energy constant of 1 joule, it must be placed across a potential difference ofA. 900 VB. 750 VC. 447.2 VD. 200 V |
Answer» Correct Answer - C `E=1/2CV^(2)` `therefore" "V=sqrt((2E)/C)=sqrt((2xx1)/(10xx10^(-6)))=447.2V` |
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