If `A=(1,2)` and B=(2,3), then find the number of elements in `(AxxB)cap(BxxA)`. The following are the steps involved in solving the above problem. Arrange them in sequential order. (A) `(AxxB)cap(BxxA)=(2,2)` (B) Given `A=(1,2)` and B=(2,3) (C) `n[)AxxB)cap(BxxA)]=1` (D) `AxxB={(1,2)(1,3)(2,2)(2,3)}` and `B xxA={(2,1),(2,2),(#,1),(3,2)}`A. BADCB. BDCAC. BCADD. BDAC

If `A=(1,2)` and B=(2,3), then find the number of elements in `(AxxB)c

1.	If `A=(1,2)` and B=(2,3), then find the number of elements in `(AxxB)cap(BxxA)`. The following are the steps involved in solving the above problem. Arrange them in sequential order. (A) `(AxxB)cap(BxxA)=(2,2)` (B) Given `A=(1,2)` and B=(2,3) (C) `n[)AxxB)cap(BxxA)]=1` (D) `AxxB={(1,2)(1,3)(2,2)(2,3)}` and `B xxA={(2,1),(2,2),(#,1),(3,2)}`A. BADCB. BDCAC. BCADD. BDAC
Answer» Correct Answer - D The sequential order is CABD.