If a^2+b^2+c^2=14 , then ab+bc+ca is always greater than , or equal to – InterviewSolution

1.

If a^2+b^2+c^2=14 , then ab+bc+ca is always greater than , or equal to 1) 02) 143) -14) -7

Answer»

(a+b+c)² = a²+b²+c²+ 2(ab+bc+ac) since (a+b+c)² ≥ 0

so, 0 ≤ 14 + 2(ab+bc+ac)=> (ab+bc+ac)≥ -14/2 ≥ -7

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