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If |a|=2, |b|=3 and a, b are mutually perpendicular, then the area of the triangle whose vertices are 0, a+b, a-b is |
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Answer» 5 `:.""` Area of triangle `=1/2|(a+b)xx(a-b)|` `=1/2|(a+b)xx(a-b)|` `=1/2|2bxxa|` `=|b|a|sin theta=3xx2sin 90^@=6` |
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