1.

If |a|=2, |b|=3 and a, b are mutually perpendicular, then the area of the triangle whose vertices are 0, a+b, a-b is

Answer»

5
1
6
8

Solution :Let position vectors of the POITS A, B C are `0, a+b, a-b`respectively and `theta=90^@`
`:.""` Area of triangle `=1/2|(a+b)xx(a-b)|`
`=1/2|(a+b)xx(a-b)|`
`=1/2|2bxxa|`
`=|b|a|sin theta=3xx2sin 90^@=6`


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