If →a=2^i+^j+^k,→b=^i+2^j+2^k,→c=^i+^j+2^k and →a×(→b×→c)=(1+α)^i+β(1+α)^j+γ(1+α)(1+β)^k, then the value of α−β−3γ is

If →a=2^i+^j+^k,→b=^i+2^j+2^k,→c=^i+^j+2^k and →a×(→b×→c

1.	If →a=2^i+^j+^k,→b=^i+2^j+2^k,→c=^i+^j+2^k and →a×(→b×→c)=(1+α)^i+β(1+α)^j+γ(1+α)(1+β)^k, then the value of α−β−3γ is
Answer» If $\to a = 2^i +^j +^k, \to b =^i + 2^j + 2^k, \to c =^i +^j + 2^k$ and $\to a \times (\to b \times \to c) =$ $(1 + α)^i + β (1 + α)^j + γ (1 + α) (1 + β)^k$ , then the value of $α - β - 3 γ$ is

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If →a=2^i+^j+^k,→b=^i+2^j+2^k,→c=^i+^j+2^k and →a×(→b×→c)=(1+α)^i+β(1+α)^j+γ(1+α)(1+β)^k, then the value of α−β−3γ is

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