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If `A=[[3,-3,4],[2,-3,4],[0,-1,1]]` , thenA. `adj(adjA)=A`B. `abs(adj(adj(A)))=1`C. `abs(adj(A))=1`D. None of these |
Answer» Correct Answer - A::B::C Here, `abs(A) = abs((3, -3, 4),(2, -3, 4),(0, -1, 1))` `= 3 (-3+4) + 3 (2-0) + 4 (-2+0)= 1 ne 0` `because adj (adjA) = abs(A)^(3-2) A = A ` ...(i) and `abs(adj (A) ) = abs(A)^(3-1) = abs(A)^(2) = 1^(2) = 1 ` Also, `abs(adj(adj(A))) = abs(A ) = 1 ` [ from Eq. (i) ] |
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