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If `A=[(a+ib,c+id),(-c+id,a-ib)]` and `a^(2)+b^(2)+c^(2)+d^(2)=1`, then `A^(-1)` is equal toA. `[(a-ib,-c-id),(c-id,a+ib)]`B. `[(a+ib,-c+id),(-c+id,a-ib)]`C. `[(a-ib,-c-id),(-c-id,a+ib)]`D. none of these |
Answer» Correct Answer - A We have, `|A|=(a+ib) (a-ib)-(-c+id) (c+id)` `=a^(2)+b^(2)+c^(2)+d^(2)=1` and adj `(A)=[(a-ib,-c-id),(c-id,a+ib)]` Then `A^(-1)=[(a-ib,-c-id),(c-id,a+ib)]` |
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