1.

If a=3hati+hatj-4hatk,b=6hati+5hatj-2hatk, then find the area of a triangle whose adjacent sides are determined by a and b.

Answer»

`12.5"SQ unit" `
`11.5"sq unit" `
`135"sq unit" `
`13.5"sq unit" `

Solution :Cross product of VECTOR a and b
`axxb=|UNDERSET(6,5,-2)underset(3,1,-4)hati,HATJ,hatk|`
`=hati(-2+20)-hatj(-6+24)+(15+6)=18hati-18hatj+9hatk`
magniutde of a and b
`|axxb|=sqrt((18)^(2)+(-18)^(2)+(9)^(2))=sqrt(729)=27`
`therefore "Areaof" Delta=(1)/(2)|axxb|=(27)/(2)=13.5"sq unit" `


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