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If a `4muF` capacitor is charged to 1 kV, then energy stored in the capacitor isA. 1 JB. 4 JC. 6 JD. 2 J |
Answer» Correct Answer - D `C=4muF,V=1kV,E=?` `E=1/2CV^(2)=(4xx10^(-6)xx10^(6))/2=2J` |
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