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if `A[{:(5,-3),(111,336):}]` and det`(-3A^(2013)+A^(2014))=alpha^(alpha)+beta^(2)(1+gamma+gamma^(2))` where `alpha,beta,gamma` are natural numbers and `(alphagtgammagtbeta)` thenA. `alpha+beta=2016`B. `alpha+beta=2023`C. `alpha+beta+gamma=2026`D. `beta+gamma=13` |
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Answer» Correct Answer - A::C::D `because-3A^(2013)+A^(2014)=A^(2013)(A-3I)` `becausedet(-3A^(2013)+A^(2014))=|A^(2012)(A-3I)|` `=|A|^(2013)|A-3I|=(2013)^(2013)(999)` `(2013)^(2013)3^(2)(1+10+10^(2))` |
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