1.

If a = ` 6 - sqrt 35`, find the value of `a^2 + 1/a^2`

Answer» `a = 6-sqrt35`
`:. a^2 = 36+35-12sqrt35 = 71-12sqrt35`
`1/a^2 = 1/(71-12sqrt35)**(71+12sqrt35)/(71-12sqrt35) = (71+12sqrt35)/(71^2-(12sqrt35)^2)`
`=>1/a^2 = (71+12sqrt35)/1`
`:. a+1/a^2 = 71-12sqrt35+71+12sqrt35 = 142`


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