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If a+α=1,b+β=2 and af(x)+αf(1x)=bx+βx,x≠0, then the value of the expression f(x)+f(1x)x+1x is |
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Answer» If a+α=1,b+β=2 and af(x)+αf(1x)=bx+βx,x≠0, then the value of the expression f(x)+f(1x)x+1x is |
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