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If (a -a')^(2) + (b-b')^(2) + c-c')^(2) =p and (ab'-a'b)^(2)+ (bc'-b'c)^(2) + (ca'-c'a)^(2) =q, then the perpendicular distnce of the line ax + by + cz=1, a'x + b'y+c'z=1 from origin, is |
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Answer» <P>`SQRT ((p)/(Q))` |
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