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If a, a1 , a2 , a3 , ..........,a2n, b are in AP and a, g1 , g2 , g3 , .....................g2n, b are in G..P. and h is the single harmonic mean of a & b, then a1 + a2n/g1g2n + a2 + a2n - 1/g2g2n -1 + an + an + 1gngn + 1 is equal to(a) 2n/h(b) 2nh(c) nh(d) n/h |
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Answer» Correct option (a) 2n/h Explanation: a1 + a2n = a2 + a2n–1 =......................= an +an+1 = a+b and g1g2n = g2.g2n–1 =.....................= gn .gn+1 = ab Also h = 2ab/ a + b Given expression = a + b/ab + a + b/ab + ........a+b/ab(n times) = n a + b/ab = n.2/h = 2n/h |
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