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If A Alone Can Do A Piece Of Work In 8 Days And B Alone Can Do The Same Work In 12 Days. How Many Days A And B Required To Finish The Same Work If They Work Togather? |
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Answer»
B alone one day work = 1/12 Both A and B one day work = (1/8 + 1/12) = (3/24 + 2/24) = 5/24 so A and B TOGETHER finish the work in 24/5 day or 4 4/5 days. A alone one day work = 1/8 B alone one day work = 1/12 Both A and B one day work = (1/8 + 1/12) = (3/24 + 2/24) = 5/24 so A and B together finish the work in 24/5 day or 4 4/5 days. |
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