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If `A` and `B` are arbitrary constants, then find the differential equation corresponding to `y=Acos(x+B)`. |
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Answer» Given equation is `y=Acos(x+B)`……..`(1)` `implies (dy)/(dx)=-Asin(x+B)`………..`(2)` `implies (d^(2)y)/(dx^(2))=-Acos(x+B)`…………`(3)` The second order derivative is taken because there are two arbitrary constants. From eqs. `(1)` and `(3)` `(d^(2)y)/(dx^(2))=-y`. |
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