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If A and B are invertible matrices of the same order then (AB)-1 = ? A. (A-1 х B-1) B. (A х B-1) C. (A-1 х B) D. (B-1 х A-1) |
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Answer» (AB)(AB)-1 = I A-1(AB)(AB)-1 = IA-1 (A -1A)B (AB) -1=A-1 IB(AB)-1 = A-1 B(AB)-1 = A-1 B-1B(AB)-1 = B-1 A-1 I (AB)-1 = B-1A-1 (AB)-1 = B-1A-1 |
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