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If A and B are invertible square matrices of the same order then (AB)-1 = ? A. AB-1 B.A-1B C.A-1B-1 D.B-1A-1 |
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Answer» (AB)(AB)-1 = I A -1(AB)(AB)-1 = IA-1 (A-1A)B (AB)-1=A-1 IB(AB)-1 = A-1 B(AB)-1 = A-1 B-1B(AB)-1 = B-1 A-1 I (AB) -1 = B -1A -1 (AB) -1 = B -1A -1 |
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