If A And B Are Positive Integers, And X=2×3×7×a , And Y=2×2×8×b

1.	If A And B Are Positive Integers, And X=2×3×7×a , And Y=2×2×8×b , And The Values Of Both X And Y Lie Between 120 And 130 (not Including The Two), Then A–b=?
Answer» We are GIVEN that x=2×3×7×a=42a and y=2×2×8×b=32b We are given that the VALUES of both x and y lie between 120 and 130 (not including the two). The only multiple of 42 in this range is 42×3=126. Hence, x=126 and a=3. The only multiple of 32 in this range is 32×4=128. Hence, y=128 and b=4. Hence, a-b=3-4= -1. We are given that x=2×3×7×a=42a and y=2×2×8×b=32b We are given that the values of both x and y lie between 120 and 130 (not including the two). The only multiple of 42 in this range is 42×3=126. Hence, x=126 and a=3. The only multiple of 32 in this range is 32×4=128. Hence, y=128 and b=4. Hence, a-b=3-4= -1.

If A And B Are Positive Integers, And X=2×3×7×a , And Y=2×2×8×b , And The Values Of Both X And Y Lie Between 120 And 130 (not Including The Two), Then A–b=?

Answer»

We are GIVEN that x=2×3×7×a=42a and y=2×2×8×b=32b

We are given that the VALUES of both x and y lie between 120 and 130 (not including the two).

The only multiple of 42 in this range is 42×3=126.

Hence, x=126 and a=3.

The only multiple of 32 in this range is 32×4=128.

Hence, y=128 and b=4.

Hence, a-b=3-4= -1.

We are given that x=2×3×7×a=42a and y=2×2×8×b=32b

We are given that the values of both x and y lie between 120 and 130 (not including the two).

The only multiple of 42 in this range is 42×3=126.

Hence, x=126 and a=3.

The only multiple of 32 in this range is 32×4=128.

Hence, y=128 and b=4.

Hence, a-b=3-4= -1.