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If α and β are the roots of 4x2 + 3x + 7 = 0, then the value of \(\frac{1}{α} + \frac{1}{β}\) isA. \(\frac{4}{7}\) B. \(-\frac{3}{7}\) C. \(\frac{3}{7}\) D. \(-\frac{3}{4}\) |
Answer» Given 4x2+ 3x + 7 = 0 We know sum of the roots = \(\frac{-3}{4}\) Product of the roots = \(\frac{7}{4}\) As given that α and β are roots then, α + β = \(\frac{-3}{4}\) α β = \(\frac{7}{4} \) Given \(\frac{1}{α} + \frac{1}{β}\) = \(\frac{α+β}{αβ}\) = \(-\frac{3}{\frac{4}{\frac{7}{4}}}\) = \(\frac{-3}{7}\) |
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