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If a and b are the roots of the equation x2 + 7x + 4 = 0 where a > b, then find the value of 2/7a + 1/3.5b + ab. |
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Answer» x2 + 7x + 4 = 0 Given that a & b are roots of this equation. ∴ a + b = -7 ab = 4 Now, \(=\frac27a + \frac1{3.5}b + ab\) \(=\frac{1}{3.5}(a+b)+ ab\) \(= \frac1{3.5}\times -7 +4\) \(= - 2 + 4\) \(= 2.\) |
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