If α and β are the roots of the equation, x2+xsinθ−2sinθ=0,θ∈ – InterviewSolution

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1.	If α and β are the roots of the equation, x2+xsinθ−2sinθ=0,θ∈(0,π2) , then α12+β12(α−12+β−12)(α−β)24 is equal to
Answer» If $α$ and $β$ are the roots of the equation, $x^{2} + x sin θ - 2 sin θ = 0, θ \in (0, \frac{π}{2})$ , then $\frac{α^{12} + β^{12}}{(α^{- 12} + β^{- 12}) (α - β)^{24}}$ is equal to

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