If α and β are the zeroes of 2x2 + 5x - 9, then the value of αβ

1.	If α and β are the zeroes of 2x2 + 5x - 9, then the value of αβ is(a) \(\frac{-5}2\) (b) \(\frac{5}2\)(c) \(\frac{-9}2\)(d) \(\frac{9}2\)
Answer» (c) \(\frac{-9}2\) Given: α and β be the zeroes of 2x² + 5x – 9. If α + β are the zeroes, then x² – (α + β) x + αβ is the required polynomial. The polynomial will be x² – \(\frac{5}2x\) - \(\frac{9}2\). ∴ αβ = \(\frac{-9}2\)

If α and β are the zeroes of 2x2 + 5x - 9, then the value of αβ is(a) \(\frac{-5}2\) (b) \(\frac{5}2\)(c) \(\frac{-9}2\)(d) \(\frac{9}2\)

Answer»

(c) \(\frac{-9}2\)

Given:

α and β be the zeroes of 2x² + 5x – 9.

If α + β are the zeroes, then x² – (α + β) x + αβ is the required polynomial.

The polynomial will be x² – \(\frac{5}2x\) - \(\frac{9}2\).

∴ αβ = \(\frac{-9}2\)