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If α and β are the zeros of the quadratic polynomial such that α + β = 24 and α - β = 8, find a quadratic polynomial having α and β as its zeros. |
Answer» A quadratic equation when sum and product of its zeros is given by: f(x) = k{x2 - (sum of zeros)x + product of the zeros}, where k is a constant α + β = 24 ....(1) α - β = 8 ....(2) Adding 1 and 2 we get, α + β + α - β = 24 + 8 ⇒ 2α = 32 ⇒ α = 16 Substitute value in 1 to get 16 + β = 24 ⇒ β = 24 -16 ⇒ β = 8 α = 16 and β = 8 f(x) = k{x2 - (24)x + 16 × 8} f(x) = k(x2 - 24x + 128) If we will put the different values of k, we will find the different quadratic equations. |
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