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If A and B are two independent events, the probability that both A and B occur is 1/8 are the probability that neither of them occours is 3/8. Find the probaility of the occurrence of A. |
Answer» We have, `P(AnnB)=1/8and P(barAnnbarB)=3/8` `thereforeP(A)P(B)=1/8and P(barA)P(barB)=3/8` `" "[therefore"A and B are independent"]` Now, `P(barAnnbarB)=3/8` `implies1-P(AnnB)=3/8` `or 1-(P(A)+P(B)-P(AnnB))=3/8` `or1-(P(A)+P(B))+1/8=3/8` `orP(A)+P(B)=3/4` The equation whose roots are P(A) and P(B) is `x^(2)-x{P(A)+P(B)}+P(A)P(B)=0` `or x^(2)-3/4x+1/8=0` `or8x^(2)-6x+1=0` `or x=1/2,1/4` |
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