1.

If α,β≠0, and f(n)=αn+βn and ∣∣∣∣∣31+f(1)1+f(2)1+f(1)1+f(2)1+f(3)1+f(2)1+f(3)1+f(4)∣∣∣∣∣=K(1−α)2(1−β)2(α−β)2, then K is equal to:

Answer»

If α,β≠0, and f(n)=αn+βn and

∣∣
∣
∣∣31+f(1)1+f(2)1+f(1)1+f(2)1+f(3)1+f(2)1+f(3)1+f(4)∣∣
∣
∣∣=K(1−α)2(1−β)2(α−β)2, then K is equal to:


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