If [(a - b,2a + c),(2a - b,3c + d)] = [(-1,5),(0,13)] then a,b,c and d

1.	If [(a - b,2a + c),(2a - b,3c + d)] = [(-1,5),(0,13)] then a,b,c and d. Find the value of a,b,c & d.
Answer» [(a - b,2a + c),(2a - b,3c + d)] = [(-1,5),(0,13)] ∴ a - b = -1 ...(i) 2a + b = 0 ...(ii) Solving (i) and (ii), we get a = 1 when a = 1, then a - b = - 1 b = 2 2a + c = 5 2 x 1 + c = 5 2 + c = 5 c = 3 3c + d = 13 3 x 3 + d = 13 d = 13 - 9 = 4

If [(a - b,2a + c),(2a - b,3c + d)] = [(-1,5),(0,13)] then a,b,c and d. Find the value of a,b,c & d.

Answer»

[(a - b,2a + c),(2a - b,3c + d)] = [(-1,5),(0,13)]

∴ a - b = -1 ...(i)

2a + b = 0 ...(ii)

Solving (i) and (ii), we get

a = 1

when a = 1, then

a - b = - 1

b = 2

2a + c = 5

2 x 1 + c = 5

2 + c = 5

c = 3

3c + d = 13

3 x 3 + d = 13

d = 13 - 9 = 4