If `A+B=90` then prove that `sqrt((tanAtanB+tanAcotB)/(sinAsecB))=secA

1.	If `A+B=90` then prove that `sqrt((tanAtanB+tanAcotB)/(sinAsecB))=secA`
Answer» `tan(90-A)=cotA` `tan B= cotA` `sinB=cosA` `cosecB=secA` `tanA=cotB` `sinA=cosB` `coseccA=secB` LHS `=sqrt((tanAcotA+tanAtanA)/(sinAcosecA))` `=sqrt(1+tan^2A)` `=sqrt(sec^2A)` `=secA`

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If `A+B=90` then prove that `sqrt((tanAtanB+tanAcotB)/(sinAsecB))=secA`

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