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If `a ,b ,a n dc`are in A.P. `p ,q ,a n dr`are in H.P., and `a p ,b q ,a n dc r`are in G.P., then `p/r+r/p`is equal to`a/c-c/a`b. `a/c+c/a`c. `b/q+q/b`d. `b/q-q/b`A. A.PB. G.PC. G.PD. none of these |
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Answer» Correct Answer - D a,b, and c are in A.P. Hence, 2b=a+c `a/(bc)+2/b=(a+2c)/(bc)ne2/c` `rArra/(bc),1/c,2/b` are not in A.P. `(bc)/a+b/2=(2bc+ab)/(2a)nec` Hence, the given numbers are not in H.P. Again, `a/(bc)2/b=(2a)/(b^(2)c)ne1/c^(2)` Therefore, the given numbers are not in G.P. |
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