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If a, b and c are the three vectors mutually perpendicular to each other to form a right handed system and |a|=1, |b|=3 and |c|=5, then [a-2b b-3c c-4a] is equal to |
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Answer» SOLUTION :GIVEN that, `|a|=1, |b|=3` and `|c|=5` `:. [(a-2b,b-3c,c-4a)]` `=(a-2b).{(b-3c)XX(c-4a)}` `=(a-2b). {bxxc-4bxx+12 xx}` `=(a-2b).(a+4c+12b)` `=a.a-24b.b=1-24xx9` `=1-216=-215` |
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