If a, b and g are the three zeroes of the polynomial p(x) = x3 – 64x

1.	If a, b and g are the three zeroes of the polynomial p(x) = x3 – 64x – 14, what is the value of α3 + β3 + γ3 ? (1) 36 (2) 40 (3) 42 (4) 64
Answer» Correct option (3) 42 Explanation: P (x) = x³ – 64x – 14 α + β + γ = 0, αβ + βγ + γα = – 64, αβγ = 14 α³ + β³ + g³ = 3αβg = 42

If a, b and g are the three zeroes of the polynomial p(x) = x3 – 64x – 14, what is the value of α3 + β3 + γ3 ? (1) 36 (2) 40 (3) 42 (4) 64

Answer»

Correct option (3) 42

Explanation:

P (x) = x³ – 64x – 14

α + β + γ = 0, αβ + βγ + γα = – 64, αβγ = 14

α³ + β³ + g³ = 3αβg = 42

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If a, b and g are the three zeroes of the polynomial p(x) = x3 – 64x – 14, what is the value of α3 + β3 + γ3 ? (1) 36 (2) 40 (3) 42 (4) 64

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