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If A , B are event such that P(A)=0.6, P(B)=0.4 and P(A cap B)=0.2, then find P( A | B^c)

Answer»

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SOLUTION :`P(A|B^c)=(P(A capB^c))/(P(B^c))=(P(A-B))/(1-P(B))=(P(A)-P(A capB))/(1-0.4)`
`=(0.6-0.2)/0.6=0.4/0.6=4/6=2/3`


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