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If α, β are roots of the equation x2 -a(x+1) - c = 0, then write the value of (1+α)(1+ β). |
Answer» given x2- a(x+1) - c = 0 x2- ax - a - c = 0 x2- ax - (a + c) = 0 as α, β are roots of equation, we get sum of the roots α + β = a Product of roots αβ = - (a + c) Given (1+ α) (1+ β) = 1 + (α + β) + (α β) = 1 + a – a – c = 1 – c. |
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