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If A,B are two events such that P(A)=0.3, P(B)=0.4,P(AcupB)=0.6 Find P(A | B^c)

Answer»

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SOLUTION :`P(A | B^c)=(P(A CAP B^c))/(P(B^c))=(P(A-B))/(1-P(B))`
`P(A)-(P(ACAPB))/(1-0.4)=(0.3-0.1)/0.6=0.2/0.6=2/6=1/3`


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