1.

If a + b + c = 0, then a2 + ab + b2 is equal to :(a) b2 – bc + c2 (b) c2 – ab (c) b2 + bc + c2 (d) 0

Answer»

(c) c2 – ab

If a + b + c = 0, then a3 + b3 + c3 – 3abc = 0 

⇒ (a + b) (a2 – ab + b2) + c3 = 3abc 

⇒ (– c) (a2 – ab + b2) + c3 = 3abc           [ (a + b) = – c] 

⇒ a2 – ab + b2 – c2 = – 3ab 

⇒ a2 – ab + b2 + 2ab – c2 = – 3ab + 2ab = a2 + ab + b2 = c2 – ab



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