Saved Bookmarks
| 1. |
If a + b + c = 0, then prove that a3 + b3 + c3 = 3abc. |
|
Answer» Given a + b + c = 0 ⇒ a + b = -c ……………..(1) Cubing on both sides (a + b)3 = (-c)3 a3 + b3 + 3ab (a + b) = -c3 a3 + b3 + 3ab (-c) =-c3 From(l) a3 + b3 – 3abc = -c3 a3 + b3 + c3 – 3abc |
|