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If a + b + c = 0, then what is the value of a4 + b4 + c4 – 2a2b2 – 2b2c2 – 2c2a2 ? |
Answer» Given, a + b + c = 0. Now, a4 + b4 + c4 – 2a2b2 – 2b2c2 – 2c2a2 = (a2 + b2 + c2)2 – 4a2b2 – 4b2c2 – 4c2a2 = [(a + b + c)2 – 2ab – 2bc – 2ca]2 – 4a2b2 – 4b2c2 – 4c2a2 = [02 – 2ab – 2bc – 2ca]2 – 4a2b2 – 4b2c2 – 4c2a2 = 4a2b2 + 4b2c2 + 4c2a2 + 8ab2c + 8abc2 + 8a2bc – 4a2b2 – 4b2c2 – 4c2a2 = 8ab2c + 8abc2 + 8a2bc = 8abc (b + c + a) = 8abc. 0 = 0. |
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