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If a + b + c = 9 and ab + bc + ca =23, then a3 + b3 + c3 − 3abc =(a) 108(b) 207(c) 669(d) 729 |
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Answer» If a + b + c = 9 and ab + bc + ca =23, then a3 + b3 + c3 − 3abc = (a) 108 (b) 207 (c) 669 (d) 729 |
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