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If `A, B, C` are angles of `Delta ABC` and `tan A tan C = 3, tan B tan C = 6`, thenA. `A = (pi)/(4)`B. `tan A tan B = 2`C. `(tan A)/(tan C) = (3)/(2)`D. `tan^(3)A+tan^(3)B=tan^(3)C+3tan A tan B tan C`

Answer» Correct Answer - A::B
If `A, B, C` are …………..
`tan A + tan B + tan C = tan A tan B tan C = 3 tan B = 6 tan A`
`:. 3 tan A + tan C = tan A`
`tan C = 3 tan A`
`:. Tna A+ 2tan A + 3 tna A = tan A. 2tan A . 3 tan a i.e.`
`tan A = tan^(3)A`
`i.e. tan^(2)A=1 i.e. tan A = 1`
`:. A = (pi)/(4)`
`:. tan A tna B = 2 tan^(2)A = 2`


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