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If `A, B, C` are angles of `Delta ABC` and `tan A tan C = 3, tan B tan C = 6`, thenA. `A = (pi)/(4)`B. `tan A tan B = 2`C. `(tan A)/(tan C) = (3)/(2)`D. `tan^(3)A+tan^(3)B=tan^(3)C+3tan A tan B tan C` |
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Answer» Correct Answer - A::B If `A, B, C` are ………….. `tan A + tan B + tan C = tan A tan B tan C = 3 tan B = 6 tan A` `:. 3 tan A + tan C = tan A` `tan C = 3 tan A` `:. Tna A+ 2tan A + 3 tna A = tan A. 2tan A . 3 tan a i.e.` `tan A = tan^(3)A` `i.e. tan^(2)A=1 i.e. tan A = 1` `:. A = (pi)/(4)` `:. tan A tna B = 2 tan^(2)A = 2` |
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