1.

If a, b, c are in G.P, show that b2 = ac.

Answer»

Given, a, b, c are in G.P.

\(\frac{b}{a}\) = \(\frac{c}{b}\)

\(\frac{a_{k+1}}{a_k}\) = constant

⇒ b2 = ac

Hence proved



Discussion

No Comment Found