If A+B+C=π and cot2θ=cot2A+cot2B+cot2C, then sin2(A−θ)sin22A+sin2 – InterviewSolution

1.	If A+B+C=π and cot2θ=cot2A+cot2B+cot2C, then sin2(A−θ)sin22A+sin2(B−θ)sin22B+sin2(C−θ)sin22C is equal to
Answer» If $A + B + C = π$ and $cot 2 θ = cot 2 A + cot 2 B + cot 2 C$ , then $\frac{sin 2 (A - θ)}{{sin}^{2} 2 A} + \frac{sin 2 (B - θ)}{{sin}^{2} 2 B} + \frac{sin 2 (C - θ)}{{sin}^{2} 2 C}$ is equal to

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