If α, β, γ are the zeros of the polynomial f(x) = ax3 + bx2 + cx + d, then 1α+1β+1γ=(a) -bd(b) cd(c) -cd(d) -ca

If α, β, γ are the zeros of the polynomial f(x) = ax3 + bx2 + cx +

1.	If α, β, γ are the zeros of the polynomial f(x) = ax3 + bx2 + cx + d, then 1α+1β+1γ=(a) -bd(b) cd(c) -cd(d) -ca
Answer» If α, β, γ are the zeros of the polynomial f(x) = ax³ + bx² + cx + d, then $\frac{1}{α} + \frac{1}{β} + \frac{1}{γ} =$ (a) $- \frac{b}{d}$ (b) $\frac{c}{d}$ (c) $- \frac{c}{d}$ (d) $- \frac{c}{a}$

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If α, β, γ are the zeros of the polynomial f(x) = ax3 + bx2 + cx + d, then 1α+1β+1γ=(a) -bd(b) cd(c) -cd(d) -ca

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