1.

If α, β, γ be the zeroes of the polynomial 2x3 + x2 – 13x + 6, then αβγ = ? (a) -3 (b) 3(c) \(\frac{-1}2\) (d) \(\frac{-13}2\)

Answer»

(a) –3 

Since, α, β and γ are the zeroes of 2x3 + x2 – 13x + 6, 

we have:

αβγ = \(\frac{-(constant\,term)}{coefficient\,of\,x^3}\) = \(\frac{-6}2\) = - 3


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